sino000

QUOTE=HawkX]

X为propeller个数，Y为gear个数。
1) 2X+3Y<=98
2) X+3Y<=200
3) X>=2Y
4) X>0
5) Y>0
求40X+60Y的最大值。
[/QUOTE]

sino000

No. There is a unique solution to this problem conditioned on the maximal revenue, which can only be achieved with the largest Y.

That means the larger Y, the larger the revenue. The maximal revenue corresponds to the largest value of Y, which is located at the top in the green shadow area.

It should be pointed out that each point in the green area, including the three edges of the triangle, satisfies all the conditions except for the maximal revenue condition, which can only be satisfied by the top point corresponding to the unique solution.

Post by HawkX
题是有问题，我在三楼说过了：没有唯一解。
直线2X+3Y=98上(28,14)和(49,0)之间随便哪一点都可以，(40,6)就是其中一个。
不过maximum revenue确定就是1960。